Java Double Number Round round(double value, int precision)

Description

Given a double value, return a new double with precision as given.

License

Open Source License

Parameter

Parameter	Description
value	The double value.
precision	The precision.

Return

A double value with the given precision.

Declaration

public static double round(double value, int precision) 

Method Source Code

//package com.java2s;
/* A utilities class for mathematics.
    /*w  w w  . j  a  va  2s. c  o m*/
 Copyright (c) 1998-2005 The Regents of the University of California.
 All rights reserved.
    
 Permission is hereby granted, without written agreement and without
 license or royalty fees, to use, copy, modify, and distribute this
 software and its documentation for any purpose, provided that the above
 copyright notice and the following two paragraphs appear in all copies
 of this software.
    
 IN NO EVENT SHALL THE UNIVERSITY OF CALIFORNIA BE LIABLE TO ANY PARTY
 FOR DIRECT, INDIRECT, SPECIAL, INCIDENTAL, OR CONSEQUENTIAL DAMAGES
 ARISING OUT OF THE USE OF THIS SOFTWARE AND ITS DOCUMENTATION, EVEN IF
 THE UNIVERSITY OF CALIFORNIA HAS BEEN ADVISED OF THE POSSIBILITY OF
 SUCH DAMAGE.
    
 THE UNIVERSITY OF CALIFORNIA SPECIFICALLY DISCLAIMS ANY WARRANTIES,
 INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
 MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE. THE SOFTWARE
 PROVIDED HEREUNDER IS ON AN "AS IS" BASIS, AND THE UNIVERSITY OF
 CALIFORNIA HAS NO OBLIGATION TO PROVIDE MAINTENANCE, SUPPORT, UPDATES,
 ENHANCEMENTS, OR MODIFICATIONS.
    
 PT_COPYRIGHT_VERSION_2
 COPYRIGHTENDKEY
 */

public class Main {
    /**
     * Given a double value, return a new double with precision as given.
     * 
     * @param value
     *            The double value.
     * @param precision
     *            The precision.
     * @return A double value with the given precision.
     */
    public static double round(double value, int precision) {
        // NOTE: when the value is too big, e.g. close to the
        // maximum double value, the following algorithm will
        // get overflow, which gives a wrong answer.
        double newValue = Math.round(value * Math.pow(10, precision)) / Math.pow(10, precision);
        return newValue;
    }
}

Related

1. round(double value, int places)
2. round(double value, int places)
3. round(double value, int power)
4. round(double value, int precision)
5. round(double value, int precision)
6. round(double value, int roundingFactor)
7. round(double value, int scalar, int standard)
8. round(double valueToRound, int numberOfDecimalPlaces)
9. round(double valueToTruncate, int requiredDecimalPlaces)