Java Double Number mod mod(double i, final double n)

Here you can find the source of mod(double i, final double n)

Description

mod

License

Open Source License

Declaration

public static double mod(double i, final double n) 

Method Source Code

//package com.java2s;
/**/* w  w  w  .  j  a va 2 s. c  om*/
 * Copyright 2015 Palantir Technologies
 *
 * Licensed under the BSD-3 License (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://opensource.org/licenses/BSD-3-Clause
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    public static double mod(double i, final double n) {
        i = 0 <= i ? i % n : (n - (-i % n)) % n;
        assert 0 <= i && i < n;
        return i;
    }

    public static int mod(int i, final int n) {
        i = 0 <= i ? i % n : (n - (-i % n)) % n;
        assert 0 <= i && i < n;
        return i;
    }
}

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  2. mod(double a, double b)
  3. Mod(double arg1, double arg2)
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  6. mod(double n, double d)
  7. mod(double number, double mod)