Java Double Number Format formatDouble(double d, int precision)

Description

Returns a string of the double with the specified floating point precision with zeroes added if required to achieve the precision.
double 10.03 with precision 4 will result in 10.0300
double 2.123456 with precision 4 will result in 2.1234

License

Open Source License

Parameter

Parameter	Description
d	a parameter
precision	a parameter

Declaration

public static String formatDouble(double d, int precision)

Method Source Code

//package com.java2s;
/**/* w  w w .ja  va2  s . c  o m*/
 * Stringter: Workbench for string editing
 *
 * Copyright (C) 2015 Zdravko Petkov
 *
 * This program is free software: you can redistribute it and/or modify it under
 * the terms of the GNU General Public License as published by the Free Software
 * Foundation, either version 3 of the License, or any later version.
 *
 * This program is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
 * FOR A PARTICULAR PURPOSE. See the GNU General Public License for more
 * details.
 *
 * You should have received a copy of the GNU General Public License along with
 * this program. If not, see <http://www.gnu.org/licenses/>.
 */

public class Main {
    /**
     * Returns a string of the double with the specified floating point precision
     * with zeroes added if required to achieve the precision.<br>
     *
     * <code>double 10.03 with precision 4 will result in 10.0300</code><br>
     * <code>double 2.123456 with precision 4 will result in 2.1234</code><br>
     *
     * @param d
     * @param precision
     * @return
     */
    public static String formatDouble(double d, int precision) {
        String result = String.valueOf(d);
        int floatingPoint = result.indexOf('.');
        int addZeroes = -(result.length() - (floatingPoint + 1) - precision);
        if (addZeroes < 0) {
            return result.substring(0, floatingPoint + 1 + precision);
        } else {
            for (int i = 0; i < addZeroes; i++) {
                result = result + "0";
            }
            return result;
        }
    }
}