Here you can find the source of hasIntersection(Collection> a, Collection> b)
Parameter | Description |
---|---|
a | <tt>Collection</tt> to be examined. |
b | the other <tt>Collection</tt> to be examined. |
public static boolean hasIntersection(Collection<?> a, Collection<?> b)
//package com.java2s; /*//w w w . j av a2 s.c o m * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.util.Collection; public class Main { /** * Returns true if <tt>Collection</CODE>s have intersection. * * @param a <tt>Collection</tt> to be examined. * @param b the other <tt>Collection</tt> to be examined. * * @return true if given <tt>Collection</tt>s have common element */ public static boolean hasIntersection(Collection<?> a, Collection<?> b) { return !isDisjoint(a, b); } /** * Returns true if <tt>Collection</CODE>s are disjoint each other. * * @param a <tt>Collection</tt> to be examined. * @param b the other <tt>Collection</tt> to be examined. * * @return true if given <tt>Collection</tt>s are disjoint each other */ public static boolean isDisjoint(Collection<?> a, Collection<?> b) { if (a == null || b == null) return true; Collection<?> tester = (a.size() < b.size()) ? a : b; Collection<?> testant = (a.size() < b.size()) ? b : a; for (Object o : tester) { if (testant.contains(o)) return false; } return true; } }