Java Collection Contain containsAnyOf(String s, Collection values)

Here you can find the source of containsAnyOf(String s, Collection values)

Description

contains Any Of

License

Open Source License

Declaration

public static boolean containsAnyOf(String s, Collection values) 

Method Source Code

//package com.java2s;
/**// w w  w  .j a va  2 s.c o  m
 * $Revision $
 * $Date $
 *
 * Copyright (C) 2005-2010 Jive Software. All rights reserved.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.ArrayList;
import java.util.Arrays;

import java.util.Collection;

import java.util.Iterator;

import java.util.List;

public class Main {
    public static boolean containsAnyOf(String s, String values[]) {
        return containsAnyOf(s, ((Collection) (Arrays.asList(values))));
    }

    public static boolean containsAnyOf(String s, Collection values) {
        if (s == null)
            return false;
        for (Iterator i$ = values.iterator(); i$.hasNext();) {
            String value = (String) i$.next();
            if (s.contains(value))
                return true;
        }

        return false;
    }

    public static List asList(String string) {
        if (string == null || "".equals(string))
            return new ArrayList();
        String tokens[] = string.split(",");
        ArrayList list = new ArrayList();
        String arr$[] = tokens;
        int len$ = arr$.length;
        for (int i$ = 0; i$ < len$; i$++) {
            String t = arr$[i$];
            try {
                long value = Long.parseLong(t);
                list.add(Long.valueOf(value));
            } catch (NumberFormatException e) {
            }
        }

        return list;
    }
}

Related

  1. containsAny(final Collection collection, final Object... items)
  2. containsAny(final Collection collection1, final Collection collection2)
  3. containsAny(final Collection a, final Collection b)
  4. containsAnyIgnoreCase(String string, Collection searchStrings)
  5. containsAnyNull(Collection source)
  6. containsAnyVariables(Collection propertyValues)
  7. containsAssignableClass( Collection> clses, Class clazz)
  8. containsAtLeastOne(Collection origin, Collection elements)
  9. containsAtleastOne(Collection left, Collection right)