Java ClassPath Get getClasspathResource(String path)

Description

get Classpath Resource

License

Apache License

Declaration

public static InputStream getClasspathResource(String path) throws IllegalArgumentException 

Method Source Code

//package com.java2s;
//License from project: Apache License 

import java.io.InputStream;

import java.net.MalformedURLException;
import java.net.URL;

public class Main {

    public static InputStream getClasspathResource(String path) throws IllegalArgumentException {
        if (path == null) {
            throw new IllegalArgumentException("the parameter 'path' is required.");
        }/*from   w  w w  .  j  av a2  s.  c om*/
        URL url = getClasspathResourceURL(path);

        if (url == null) {
            throw new IllegalArgumentException("the resource path[" + path + "] could not be found.");
        }

        InputStream inStream;
        try {
            inStream = url.openStream();
        } catch (Throwable e) {
            throw new IllegalArgumentException("It failed to get the resource[" + url + "].", e);
        }
        return inStream;
    }

    public static URL getClasspathResourceURL(String path) {
        if (path == null) {
            throw new IllegalArgumentException("the parameter 'path' is required.");
        }
        ClassLoader loader = Thread.currentThread().getContextClassLoader();
        return loader.getResource(path);
    }

    public static InputStream getResource(String url) throws IllegalArgumentException {
        URL resourceURL = getResourceURL(url);
        try {
            return resourceURL.openStream();
        } catch (Throwable e) {
            throw new IllegalArgumentException("resource open failed. url = [" + url + "].", e);
        }
    }

    public static URL getResourceURL(String url) {
        if (url == null) {
            throw new IllegalArgumentException("the parameter 'url' is required.");
        }
        if (url.startsWith("classpath:")) {
            return getClasspathResourceURL(url.substring("classpath:".length()));
        }
        try {
            return new URL(url);
        } catch (MalformedURLException e) {
            throw new IllegalArgumentException(String.format("illegal url was specified. path=[%s]", url), e);
        }
    }
}

Related

1. getClasspathForClass(Class targetClass)
2. getClassPathFromString(String classpath)
3. getClassPathPath()
4. getClasspathResource(final String resource)
5. getClasspathResource(String name)
6. getClasspathResourceAsFile(String resourceName)
7. getClassPathResourcesAsStreams(String relativeResourceName)
8. getClassPathRoot(Class cl)
9. getClasspathString()