Java Utililty Methods Byte Array to Long

return fromBytes(bytes, off, 8);

return bigEndian ? bytesToLongBE(bytes, off) : bytesToLongLE(bytes, off);

int offset = 0;
long a1 = data[offset + 3] & 0xFF;
long a2 = data[offset + 2] & 0xFF;
long a3 = data[offset + 1] & 0xFF;
long a4 = data[offset + 0] & 0xFF;
long res1 = (a1) + (a2 << 8) + (a3 << 16) + (a4 << 24);
offset += 4;
long b1 = data[offset + 3] & 0xFF;
...

long n = 0xffL & data[0];
for (int i = 1; i < 8; i++) {
    n = (n << 8) | (0xffL & data[i]);
return n;

if (data.length > 8)
    throw new RuntimeException("array too long to convert to long");
long result = 0;
for (byte x : data)
    result = (result << 8) | (x & 0xff);
return result;

long num = 0;
for (int i = offset; i < offset + 8; i++) {
    num <<= 8;
    num |= (data[i] & 0xff);
return num;

long result = 0;
for (int i = 0 + shift; i < 8 + shift; i++) {
    result = (result << 8) + (inbytes[i] & 0xff); 
return result;

byte[] data = new byte[8];
System.arraycopy(longBytes, 0, data, 0, 8);
int mask = 0xff;
long temp = 0;
long res = 0;
for (int i = 0; i < 8; i++) {
    res <<= 8;
    temp = data[i] & mask;
...

return l(p[offset]) | (l(p[offset + 1]) << 8) | (l(p[offset + 2]) << 16) | (l(p[offset + 3]) << 24)
        | (l(p[offset + 4]) << 32) | (l(p[offset + 5]) << 40) | (l(p[offset + 6]) << 48)
        | (l(p[offset + 7]) << 56);

return bytesToLong(b, 0);