Java Bits Convert to bitsRequired(double minValue, double maxValue)

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Description

computes the required number of bits to represent an range minValue...maxValue / 0..max(minValue,maxValue) In case on of the minValue < 0 also the bit for the sign is included

License

LGPL

Declaration 

public static int bitsRequired(double minValue, double maxValue)

Method Source Code

//package com.java2s;
//License from project: LGPL 

public class Main {
    /**/*w  w w . j a v a2 s.c om*/
    * computes the required number of bits to represent an range
    * minValue...maxValue / 0..max(minValue,maxValue)
    * In case on of the minValue < 0 also the bit for the sign is included
    *
    */
    public static int bitsRequired(double minValue, double maxValue) {
        long absmax = (long) Math.max(Math.abs(minValue), maxValue) + 1;

        int bits = 64 - Long.numberOfLeadingZeros(absmax);

        if (minValue < 0.0)
            bits++;

        return bits;
    }
}

Related

  1. bits2Numeric(boolean[] in)
  2. bitsArrayToByte(byte[] bits)
  3. bitscanForward(long bitboard)
  4. bitsCleanup(int base, int[] bits)
  5. BitsNeeded(int n)
  6. bitsRequired(int value)
  7. bitsRequiredForFraction(String floatnumber)
  8. bitsString2(byte b)
  9. bitsTo8Bytes(boolean[] bits)