Java BigInteger Reverse reverse(BigInteger currentSum)

Here you can find the source of reverse(BigInteger currentSum)

Description

reverse

License

Apache License

Parameter

Parameter Description
currentSum a parameter

Declaration

public static BigInteger reverse(BigInteger currentSum) 

Method Source Code

//package com.java2s;
/**//from  ww  w . j  a v  a2s  .  c  o m
 *
 * maer - Solutions to problems of Project Euler
 * Copyright (C) 2011, Sandeep Gupta
 * http://www.sangupta.com/projects/maer
 *
 * The file is licensed under the the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 */

import java.math.BigInteger;

public class Main {
    /**
     * @param currentSum
     * @return
     */
    public static BigInteger reverse(BigInteger currentSum) {
        String num = currentSum.toString();
        String rev = new StringBuilder(num).reverse().toString();
        BigInteger revNum = new BigInteger(rev);
        return revNum;
    }
}

Related

  1. reverse(BigInteger n)
  2. reverse(BigInteger x, int width)