Java Utililty Methods Array Sum

List of utility methods to do Array Sum

Description

The list of methods to do Array Sum are organized into topic(s).

Method

intsummarizeIntegerArray(int[] numbers)
Takes an array of integers and return the summation
int total = 0;
for (int number : numbers) {
    total += number;
return total;
String[]summarizeNumbersAsString(int[] numbers)
Return a list of strings were adjacent values are clumped together.
Set<Integer> set = new HashSet<Integer>();
for (int number : numbers) {
    set.add(number);
List<Integer> sortedNumbers = new ArrayList<Integer>(set);
Collections.sort(sortedNumbers);
List<String> summarizedStrings = new ArrayList<String>();
Integer currentRunMin = null;
...
doublesummation(double[] values)
summation
double sum = 0.0;
int size = values.length;
for (int i = 0; i < size; i++) {
    sum += values[i];
return sum;
doublesumMaxK(double[] x, int k)
sum Max K
int[] ids = sort(x);
if (k > ids.length) {
    k = ids.length;
double s = 0;
for (int i = ids.length - 1; (ids.length - 1 - i + 1) <= k; i--) {
    s = s + x[ids[i]];
return s;
intsummedDifference(int[][] matrix, short topX, short botX, short row)
summed Difference
int n = matrix[0].length - 1;
int sums[] = new int[4];
sums[1] = matrix[topX][row];
sums[0] = matrix[n][row] - sums[1];
sums[2] = matrix[botX][n] - matrix[botX][row];
sums[3] = matrix[n][n] - sums[0] - sums[2] - sums[1];
Arrays.sort(sums);
return sums[3] - sums[0];
...
doublesumMinMax(double[] values, int out[])
The sum of the entries in the specified portion of the input array, or Double.NaN if the designated subarray is empty.
int max = 0;
int min = 0, i;
double sum = values[0];
int n = values.length;
for (i = 1; i < n; i++) {
    sum += values[i];
    if (values[i] > values[max])
        max = i;
...
doublesumMult(double[] aArray1, double[] aArray2)
Computes the sum of the multiplications of the given arrays.
double result = 0;
for (int i = 0; i < aArray1.length; ++i) {
    result += aArray1[i] * aArray2[i];
return result;
doublesumNaive(final double... values)
sum Naive
double ret = 0;
for (final double x : values)
    ret += x;
return ret;
intsumOf(int... values)
Return the sum of all given Integer values
int retval = 0;
for (int value : values) {
    retval += value;
return retval;
doublesumOfArray(double[] array)
sum Of Array
double sum = 0;
for (double x : array) {
    sum += x;
return sum;