Java Array Remove removeUser(String[] array, String user)

Here you can find the source of removeUser(String[] array, String user)

Description

remove User

License

Apache License

Declaration

public static String[] removeUser(String[] array, String user) 

Method Source Code

//package com.java2s;
/*******************************************************************************
 * Copyright 2012-2013 Trento RISE//w  ww .j a  va  2s.  c  om
 * 
 *    Licensed under the Apache License, Version 2.0 (the "License");
 *    you may not use this file except in compliance with the License.
 *    You may obtain a copy of the License at
 * 
 *        http://www.apache.org/licenses/LICENSE-2.0
 * 
 *    Unless required by applicable law or agreed to in writing, software
 *    distributed under the License is distributed on an "AS IS" BASIS,
 *    WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *    See the License for the specific language governing permissions and
 *    limitations under the License.
 ******************************************************************************/

import java.util.ArrayList;
import java.util.Arrays;

import java.util.List;

public class Main {
    public static String[] removeUser(String[] array, String user) {
        if (array == null)
            return new String[0];
        List<String> list = new ArrayList<String>(Arrays.asList(array));
        if (list.contains(user)) {
            list.remove(user);
            return list.toArray(new String[list.size()]);
        }
        return array;
    }
}

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