Java Utililty Methods Array Min Value

int m = Integer.MAX_VALUE;
for (int v : values) {
    if (v < m) {
        m = v;
return m;

if (array == null || array.length == 0)
    throw new IllegalArgumentException();
long min = array[0];
for (int i = 1, j = array.length; i < j; i++) {
    if (min > array[i]) {
        min = array[i];
return min;

double min = Double.MAX_VALUE;
for (final Number n : numbers) {
    final double d = n.doubleValue();
    min = Math.min(min, d);
return min;

T min = elements[0];
for (final T element : elements) {
    if (0 > element.compareTo(min)) {
        min = element;
return min;

float min = a[0][0][0];
for (int i = 0; i < a.length; i++)
    for (int j = 0; j < a[i].length; j++)
        for (int k = 0; k < a[i][j].length; k++)
            min = (a[i][j][k] < min ? a[i][j][k] : min);
return min;

float ret = Float.MAX_VALUE;
for (float f : fs) {
    ret = Math.min(ret, f);
return ret;

float result = values[0];
for (int i = 1; i < values.length; i++)
    result = Math.min(result, values[i]);
return result;

float min = values[0];
for (int i = 1; i < values.length; ++i) {
    if (min > values[i]) {
        min = values[i];
return min;

int i, size = array.length;
float m = array[0];
for (i = 1; i < size; i++)
    m = Math.min(m, array[i]);
return m;

for (int i = 0; i < array.length; i++) {
    array[i] = Math.min(array[i], min);
return array;