Here you can find the source of max(final double[] nums)
public static double max(final double[] nums)
//package com.java2s; /*//w w w . j a va 2 s . c o m * The MIT License * * Copyright (c) 2011 The Broad Institute * * Permission is hereby granted, free of charge, to any person obtaining a copy * of this software and associated documentation files (the "Software"), to deal * in the Software without restriction, including without limitation the rights * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell * copies of the Software, and to permit persons to whom the Software is * furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included in * all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN * THE SOFTWARE. */ public class Main { /** Returns the largest value stored in the array. */ public static double max(final double[] nums) { return nums[indexOfMax(nums)]; } /** * Returns the index of the largest element in the array. If there are multiple equal maxima then * the earliest one in the array is returned. */ public static int indexOfMax(final double[] nums) { double max = nums[0]; int index = 0; for (int i = 1; i < nums.length; ++i) { if (nums[i] > max) { max = nums[i]; index = i; } } return index; } }