Java Array Common Prefix longestCommonSequence(String str1, String str2)

Here you can find the source of longestCommonSequence(String str1, String str2)

Description

longest Common Sequence

License

Apache License

Declaration

public static int longestCommonSequence(String str1, String str2) 

Method Source Code

//package com.java2s;
/*/*from w ww. j a v a 2 s  .c  om*/
 * Copyright [2017] [Haibo(Tristan) Yan]
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    public static int longestCommonSequence(String str1, String str2) {
        if (str1 == null || str2 == null || str1.length() == 0 || str2.length() == 0) {
            return 0;
        }

        char[] cs1 = str1.toCharArray(), cs2 = str2.toCharArray();

        int[][] longest = new int[str1.length() + 1][str2.length() + 1];

        for (int i = 0; i <= str1.length(); i++) {
            longest[i][0] = 0;
        }

        for (int i = 0; i <= str2.length(); i++) {
            longest[0][i] = 0;
        }

        for (int i = 1; i <= str1.length(); i++) {
            for (int j = 1; j <= str2.length(); j++) {
                int max = Integer.max(longest[i - 1][j], longest[i][j - 1]);

                if (cs1[i - 1] == cs2[j - 1]) {
                    max = Integer.max(longest[i - 1][j - 1] + 1, max);
                }
                longest[i][j] = max;
            }
        }

        return longest[str1.length()][str2.length()];
    }
}

Related

  1. longestCommonPrefix(String[] strs, int l, int r)
  2. longestCommonPrefix1(String[] strs)
  3. longestCommonPrefix2(String[] strs)
  4. longestCommonPrefix3(String[] strs)
  5. longestCommonPrefix4(String[] strs)
  6. longestCommonSubstr(String s1, String s2)
  7. LongestCommonSubString(String firstString, String secondString)
  8. longestCommonSubstring(String S1, String S2)
  9. longestCommonSuffix(final byte[] seq1, final byte[] seq2, final int maxLength)