Java tutorial
/* * Copyright (C) 2010, Google Inc. * and other copyright owners as documented in the project's IP log. * * This program and the accompanying materials are made available * under the terms of the Eclipse Distribution License v1.0 which * accompanies this distribution, is reproduced below, and is * available at http://www.eclipse.org/org/documents/edl-v10.php * * All rights reserved. * * Redistribution and use in source and binary forms, with or * without modification, are permitted provided that the following * conditions are met: * * - Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * * - Redistributions in binary form must reproduce the above * copyright notice, this list of conditions and the following * disclaimer in the documentation and/or other materials provided * with the distribution. * * - Neither the name of the Eclipse Foundation, Inc. nor the * names of its contributors may be used to endorse or promote * products derived from this software without specific prior * written permission. * * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND * CONTRIBUTORS "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, * INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES * OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR * CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, * SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; * LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER * CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, * STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) * ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF * ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. */ package org.eclipse.jgit.diff; /** * Equivalence function for a {@link org.eclipse.jgit.diff.Sequence} compared by * difference algorithm. * <p> * Difference algorithms can use a comparator to compare portions of two * sequences and discover the minimal edits required to transform from one * sequence to the other sequence. * <p> * Indexes within a sequence are zero-based. * * @param <S> * type of sequence the comparator supports. */ public abstract class SequenceComparator<S extends Sequence> { /** * Compare two items to determine if they are equivalent. * * It is permissible to compare sequence {@code a} with itself (by passing * {@code a} again in position {@code b}). * * @param a * the first sequence. * @param ai * item of {@code ai} to compare. * @param b * the second sequence. * @param bi * item of {@code bi} to compare. * @return true if the two items are identical according to this function's * equivalence rule. */ public abstract boolean equals(S a, int ai, S b, int bi); /** * Get a hash value for an item in a sequence. * * If two items are equal according to this comparator's * {@link #equals(Sequence, int, Sequence, int)} method, then this hash * method must produce the same integer result for both items. * * It is not required for two items to have different hash values if they * are unequal according to the {@code equals()} method. * * @param seq * the sequence. * @param ptr * the item to obtain the hash for. * @return hash the hash value. */ public abstract int hash(S seq, int ptr); /** * Modify the edit to remove common leading and trailing items. * * The supplied edit {@code e} is reduced in size by moving the beginning A * and B points so the edit does not cover any items that are in common * between the two sequences. The ending A and B points are also shifted to * remove common items from the end of the region. * * @param a * the first sequence. * @param b * the second sequence. * @param e * the edit to start with and update. * @return {@code e} if it was updated in-place, otherwise a new edit * containing the reduced region. */ public Edit reduceCommonStartEnd(S a, S b, Edit e) { // Skip over items that are common at the start. // while (e.beginA < e.endA && e.beginB < e.endB && equals(a, e.beginA, b, e.beginB)) { e.beginA++; e.beginB++; } // Skip over items that are common at the end. // while (e.beginA < e.endA && e.beginB < e.endB && equals(a, e.endA - 1, b, e.endB - 1)) { e.endA--; e.endB--; } return e; } }