net.ageto.gyrex.impex.common.steps.impl.copy.FileCopyToDirectory.java Source code

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Here is the source code for net.ageto.gyrex.impex.common.steps.impl.copy.FileCopyToDirectory.java

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/*******************************************************************************
 * Copyright (c) 2010 AGETO Service GmbH and others.
 * All rights reserved.
 *
 * This program and the accompanying materials are made available under the
 * terms of the Eclipse Public License v1.0 which accompanies this distribution,
 * and is available at http://www.eclipse.org/legal/epl-v10.html.
 *
 * Contributors:
 *     Mario Mokros - initial API and implementation
 *******************************************************************************/
package net.ageto.gyrex.impex.common.steps.impl.copy;

import java.io.File;
import java.io.IOException;

import net.ageto.gyrex.impex.common.steps.internal.ImpexStepsActivator;
import net.ageto.gyrex.impex.impl.BaseProcessStep;

import org.apache.commons.io.FileUtils;

/**
 * Copies a file to a new location preserving the file date.
 *
 */
public class FileCopyToDirectory extends BaseProcessStep<FileCopyToDirectoryDefinition> {

    public static final String ID = ImpexStepsActivator.SYMBOLIC_NAME + ".file.copy";

    public FileCopyToDirectory() {
        super(FileCopyToDirectoryDefinition.class);
    }

    @Override
    protected StatusStep process() {

        try {
            String sourceFilename = (String) getInputParam(
                    FileCopyToDirectoryDefinition.InputParamNames.SOURCE_FILENAME.name());

            File sourceFile = new File(sourceFilename);
            if (!sourceFile.isFile()) {
                processError("The source is not a valid file.");
                return StatusStep.ERROR;
            }

            String destinationFilename = (String) getInputParam(
                    FileCopyToDirectoryDefinition.OutputParamNames.DESTINATION_FILENAME.name());

            File destinationFile = new File(destinationFilename);

            // copy file
            FileUtils.copyFile(sourceFile, destinationFile);

        } catch (IOException e) {
            processError("File could not be created.");
        }

        processInfo("{0} has been completed successfully.", ID);

        return StatusStep.OK;
    }
}