Java tutorial
/* * Copyright (C) 2017 Vincze Tamas Zoltan (www.vitamas.hu) * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package hu.vitamas.enotesz.util; import java.util.HashMap; import org.slf4j.Logger; import org.slf4j.LoggerFactory; import com.google.gson.FieldNamingPolicy; import com.google.gson.Gson; import com.google.gson.GsonBuilder; import hu.vitamas.enotesz.dao.UsersDao; import hu.vitamas.enotesz.json.AuthResponse; import hu.vitamas.enotesz.model.Users; /** * Authentication/session handler class. * * @author vitozy */ public class Auth { static Logger logger = LoggerFactory.getLogger(Auth.class); private static Integer userID = 0; private static boolean loggedIn = false; /** * Returns with the logged in user's id. * * @return the logged in user's id */ public static Integer getUserID() { return userID; } /** * Returns with the logged in user instance. * * @return logged in user instance */ public static Users getUser() { UsersDao udao = new UsersDao(); return udao.findById(Auth.getUserID(), Users.class); } /** * Sets the logged in user's id. * * @param userID user id of current session */ public static void setUserID(Integer userID) { Auth.userID = userID; } /** * Gets the status of logged in. * * @return logged in status */ public static boolean isLoggedIn() { return loggedIn; } /** * Sets the status of logged in. * * @param loggedIn status of logged in */ public static void setLoggedIn(boolean loggedIn) { Auth.loggedIn = loggedIn; } /** * Checks the user is logged in or not. * * <p>This method communicate with the eNotesz server. * <p><b>Must to send API request because of encryption.</b> * * @param name name of user * @param password password of user * @return AuthResponse */ public static AuthResponse check(String name, String password) { String apiKey = Core.getApiKey(); String apiLink = Core.getApiBaseUrl(); if (apiKey == null || apiLink == null) return null; HashMap<String, String> params = MapBuilder.<String, String>newHashMap().set("pass", password) .set("name", name).set("apiKey", apiKey).build(); try { String response = Core.createApi().setMethod("POST").setUrl(apiLink + "user/checkUser") .setParams(params).sendRequest(); if (response == null) return null; Gson gson = new GsonBuilder().setFieldNamingPolicy(FieldNamingPolicy.LOWER_CASE_WITH_UNDERSCORES) .create(); return gson.fromJson(response, AuthResponse.class); } catch (Exception e) { logger.error("api or gson error", e); } return null; } }