Java tutorial
/* * @(#)UriQueryString.java 4 Aug 2011 * * Copyright 2010 Andrew Phillips. * * ==================================================================== * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or * implied. * See the License for the specific language governing permissions and * limitations under the License. * ==================================================================== */ package ext.deployit.community.cli.plainarchive.base; import static com.google.common.base.Preconditions.checkArgument; import java.util.Map; import java.util.regex.Pattern; import javax.annotation.Nonnull; import com.google.common.base.Splitter; import com.google.common.collect.ImmutableMap; import com.google.common.collect.ImmutableMap.Builder; /** * @author aphillips * @since 4 Aug 2011 * */ public class UriQueryStrings { private static final char ATTRIBUTES_SEPARATOR = '&'; // used in regex private static final String ATTRIBUTE_KEY_VALUE_SEPARATOR = Pattern.quote("="); public static @Nonnull Map<String, String> toMap(@Nonnull String queryString) { final Builder<String, String> inProgress = ImmutableMap.builder(); for (String keyValue : Splitter.on(ATTRIBUTES_SEPARATOR).split(queryString)) { String[] keyAndValue = keyValue.split(ATTRIBUTE_KEY_VALUE_SEPARATOR); checkArgument(keyAndValue.length == 2, "Invalid query string format. Expected 'key=value&key2=value&...' but found section '%s'", keyValue); inProgress.put(keyAndValue[0], keyAndValue[1]); } return inProgress.build(); } }