Java tutorial
import java.io.File; /* * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. * * */ public class Main { /** * Returns n!. Shorthand for <code>n</code> <a * href="http://mathworld.wolfram.com/Factorial.html"> Factorial</a>, the * product of the numbers <code>1,...,n</code>. * <p> * <Strong>Preconditions</strong>: * <ul> * <li> <code>n >= 0</code> (otherwise * <code>IllegalArgumentException</code> is thrown)</li> * <li> The result is small enough to fit into a <code>long</code>. The * largest value of <code>n</code> for which <code>n!</code> < * Long.MAX_VALUE</code> is 20. If the computed value exceeds <code>Long.MAX_VALUE</code> * an <code>ArithMeticException </code> is thrown.</li> * </ul> * </p> * * @param n argument * @return <code>n!</code> * @throws ArithmeticException if the result is too large to be represented * by a long integer. * @throws IllegalArgumentException if n < 0 */ public static long factorial(final int n) { long result = Math.round(factorialDouble(n)); if (result == Long.MAX_VALUE) { throw new ArithmeticException("result too large to represent in a long integer"); } return result; } /** * Returns n!. Shorthand for <code>n</code> <a * href="http://mathworld.wolfram.com/Factorial.html"> Factorial</a>, the * product of the numbers <code>1,...,n</code> as a <code>double</code>. * <p> * <Strong>Preconditions</strong>: * <ul> * <li> <code>n >= 0</code> (otherwise * <code>IllegalArgumentException</code> is thrown)</li> * <li> The result is small enough to fit into a <code>double</code>. The * largest value of <code>n</code> for which <code>n!</code> < * Double.MAX_VALUE</code> is 170. If the computed value exceeds * Double.MAX_VALUE, Double.POSITIVE_INFINITY is returned</li> * </ul> * </p> * * @param n argument * @return <code>n!</code> * @throws IllegalArgumentException if n < 0 */ public static double factorialDouble(final int n) { if (n < 0) { throw new IllegalArgumentException("must have n >= 0 for n!"); } return Math.floor(Math.exp(factorialLog(n)) + 0.5); } /** * Returns the natural logarithm of n!. * <p> * <Strong>Preconditions</strong>: * <ul> * <li> <code>n >= 0</code> (otherwise * <code>IllegalArgumentException</code> is thrown)</li> * </ul></p> * * @param n argument * @return <code>n!</code> * @throws IllegalArgumentException if preconditions are not met. */ public static double factorialLog(final int n) { if (n < 0) { throw new IllegalArgumentException("must have n > 0 for n!"); } double logSum = 0; for (int i = 2; i <= n; i++) { logSum += Math.log((double) i); } return logSum; } }