Java tutorial
//package com.java2s; /* * Copyright (C) 2012 Jason Gedge <www.gedge.ca> * * Permission is hereby granted, free of charge, to any person obtaining a * copy of this software and associated documentation files (the "Software"), * to deal in the Software without restriction, including without limitation * the rights to use, copy, modify, merge, publish, distribute, sublicense, * and/or sell copies of the Software, and to permit persons to whom the * Software is furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included * in all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER * DEALINGS IN THE SOFTWARE. */ public class Main { /** * Finds the length of the largest prefix for two character sequences. * * @param a character sequence * @param b character sequence * @return the length of largest prefix of <code>a</code> and <code>b</code> * @throws IllegalArgumentException if either <code>a</code> or <code>b</code> * is <code>null</code> */ public static int largestPrefixLength(CharSequence a, CharSequence b) { int len = 0; for (int i = 0; i < Math.min(a.length(), b.length()); ++i) { if (a.charAt(i) != b.charAt(i)) break; ++len; } return len; } }