Main.java Source code

Java tutorial

Introduction

Here is the source code for Main.java

Source

//package com.java2s;
/*
 * Copyright (C) 2012 Jason Gedge <www.gedge.ca>
 * 
 * Permission is hereby granted, free of charge, to any person obtaining a
 * copy of this software and associated documentation files (the "Software"),
 * to deal in the Software without restriction, including without limitation
 * the rights to use, copy, modify, merge, publish, distribute, sublicense,
 * and/or sell copies of the Software, and to permit persons to whom the
 * Software is furnished to do so, subject to the following conditions:
 * 
 *     The above copyright notice and this permission notice shall be included
 *     in all copies or substantial portions of the Software.
 * 
 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
 * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
 * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER
 * DEALINGS IN THE SOFTWARE.
 */

public class Main {
    /**
     * Finds the length of the largest prefix for two character sequences.
     *
     * @param a character sequence
     * @param b character sequence
     * @return the length of largest prefix of <code>a</code> and <code>b</code>
     * @throws IllegalArgumentException if either <code>a</code> or <code>b</code>
     *                                  is <code>null</code>
     */
    public static int largestPrefixLength(CharSequence a, CharSequence b) {
        int len = 0;
        for (int i = 0; i < Math.min(a.length(), b.length()); ++i) {
            if (a.charAt(i) != b.charAt(i))
                break;
            ++len;
        }
        return len;
    }
}