Java tutorial
//package com.java2s; /* * Copyright (C) 2009 Google Inc. * * Licensed under the Apache License, Version 2.0 (the "License"); you may not * use this file except in compliance with the License. You may obtain a copy of * the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the * License for the specific language governing permissions and limitations under * the License. */ import android.text.TextUtils; public class Main { /** * Takes a character sequence with a single character and checks if the character occurs * in a list of word separators or is empty. * @param singleChar A CharSequence with null, zero or one character * @param wordSeparators A String containing the word separators * @return true if the character is at a word boundary, false otherwise */ private static boolean isWordBoundary(CharSequence singleChar, String wordSeparators) { return TextUtils.isEmpty(singleChar) || wordSeparators.contains(singleChar); } }