Java tutorial
//package com.java2s; /* * Copyright (C) 2009 Google Inc. * * Licensed under the Apache License, Version 2.0 (the "License"); you may not * use this file except in compliance with the License. You may obtain a copy of * the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the * License for the specific language governing permissions and limitations under * the License. */ import android.view.inputmethod.InputConnection; import java.util.regex.Pattern; public class Main { /** * Number of characters we want to look back in order to identify the previous word */ private static final int LOOKBACK_CHARACTER_NUM = 15; private static final Pattern spaceRegex = Pattern.compile("\\s+"); public static CharSequence getPreviousWord(InputConnection connection, String sentenceSeperators) { //TODO: Should fix this. This could be slow! CharSequence prev = connection.getTextBeforeCursor(LOOKBACK_CHARACTER_NUM, 0); if (prev == null) { return null; } String[] w = spaceRegex.split(prev); if (w.length >= 2 && w[w.length - 2].length() > 0) { char lastChar = w[w.length - 2].charAt(w[w.length - 2].length() - 1); if (sentenceSeperators.contains(String.valueOf(lastChar))) { return null; } return w[w.length - 2]; } else { return null; } } }