Java tutorial
//package com.java2s; import java.text.DecimalFormat; public class Main { private static final int canonicalFloatNaN = Float.floatToRawIntBits(Float.NaN); private static final int maxFloat = Float.floatToRawIntBits(Float.MAX_VALUE); private static final int piFloat = Float.floatToRawIntBits((float) Math.PI); private static final int eFloat = Float.floatToRawIntBits((float) Math.E); private static final DecimalFormat format = new DecimalFormat("0.####################E0"); public static boolean isLikelyFloat(int value) { // Check for some common named float values // We don't check for Float.MIN_VALUE, which has an integer representation of 1 if (value == canonicalFloatNaN || value == maxFloat || value == piFloat || value == eFloat) { return true; } // Check for some named integer values if (value == Integer.MAX_VALUE || value == Integer.MIN_VALUE) { return false; } // Check for likely resource id int packageId = value >> 24; int resourceType = value >> 16 & 0xff; int resourceId = value & 0xffff; if ((packageId == 0x7f || packageId == 1) && resourceType < 0x1f && resourceId < 0xfff) { return false; } // a non-canocical NaN is more likely to be an integer float floatValue = Float.intBitsToFloat(value); if (Float.isNaN(floatValue)) { return false; } // Otherwise, whichever has a shorter scientific notation representation is more likely. // Integer wins the tie String asInt = format.format(value); String asFloat = format.format(floatValue); // try to strip off any small imprecision near the end of the mantissa int decimalPoint = asFloat.indexOf('.'); int exponent = asFloat.indexOf("E"); int zeros = asFloat.indexOf("000"); if (zeros > decimalPoint && zeros < exponent) { asFloat = asFloat.substring(0, zeros) + asFloat.substring(exponent); } else { int nines = asFloat.indexOf("999"); if (nines > decimalPoint && nines < exponent) { asFloat = asFloat.substring(0, nines) + asFloat.substring(exponent); } } return asFloat.length() < asInt.length(); } }