Java tutorial
/* * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ /** * <p>Provides extra functionality for Java Number classes.</p> * * @author <a href="mailto:rand_mcneely@yahoo.com">Rand McNeely</a> * @author Stephen Colebourne * @author <a href="mailto:steve.downey@netfolio.com">Steve Downey</a> * @author Eric Pugh * @author Phil Steitz * @author Matthew Hawthorne * @author <a href="mailto:ggregory@seagullsw.com">Gary Gregory</a> * @author <a href="mailto:fredrik@westermarck.com">Fredrik Westermarck</a> * @since 2.0 * @version $Id: NumberUtils.java 609475 2008-01-06 23:58:59Z bayard $ */ public class Main { /** * <p>Returns the maximum value in an array.</p> * * @param array an array, must not be null or empty * @return the minimum value in the array * @throws IllegalArgumentException if <code>array</code> is <code>null</code> * @throws IllegalArgumentException if <code>array</code> is empty * @see IEEE754rUtils#max(double[]) IEEE754rUtils for a version of this method that handles NaN differently */ public static double max(double[] array) { // Validates input if (array == null) { throw new IllegalArgumentException("The Array must not be null"); } else if (array.length == 0) { throw new IllegalArgumentException("Array cannot be empty."); } // Finds and returns max double max = array[0]; for (int j = 1; j < array.length; j++) { if (Double.isNaN(array[j])) { return Double.NaN; } if (array[j] > max) { max = array[j]; } } return max; } }