Write code to Checks if the String contains any character in the given set of characters.
containsAny(null, *) = false containsAny("", *) = false containsAny(*, null) = false containsAny(*, []) = false containsAny("zzabyycdxx",['z','a']) = true containsAny("zzabyycdxx",['b','y']) = true containsAny("aba", ['z']) = false
Use nested for loop
public class Main{ public static void main(String[] argv){ String str = "book2s.com"; char[] searchChars = new char[]{'b','o','o','k','2','s','.','c','o','m','a','1',}; System.out.println(containsAny(str,searchChars)); }/*from w w w .ja v a 2s. co m*/ /** * <p> * Checks if the String contains any character in the given set of * characters. * </p> * * <p> * A <code>null</code> String will return <code>false</code>. A * <code>null</code> or zero length search array will return * <code>false</code>. * </p> * * <pre> * containsAny(null, *) = false * containsAny("", *) = false * containsAny(*, null) = false * containsAny(*, []) = false * containsAny("zzabyycdxx",['z','a']) = true * containsAny("zzabyycdxx",['b','y']) = true * containsAny("aba", ['z']) = false * </pre> * * @param str * the String to check, may be null * @param searchChars * the chars to search for, may be null * @return the <code>true</code> if any of the chars are found, * <code>false</code> if no match or null input * @since 2.4 */ public static boolean containsAny(String str, char[] searchChars) { int csLength = str.length(); int searchLength = searchChars.length; for (int i = 0; i < csLength; i++) { char ch = str.charAt(i); for (int j = 0; j < searchLength; j++) { if (searchChars[j] == ch) { return true; } } } return false; } }