Example usage for java.util AbstractSet addAll

Introduction

In this page you can find the example usage for java.util AbstractSet addAll.

Prototype

boolean addAll(Collection<? extends E> c);

Source Link

Document

Adds all of the elements in the specified collection to this set if they're not already present (optional operation).

Usage

From source file:org.ontologyengineering.conceptdiagrams.web.shared.concretesyntax.ConcreteDiagram.java

public AbstractSet<ConcreteDiagramElement> elementsInBoundingBox(Point topLeft, Point botRight) {
    AbstractSet<ConcreteDiagramElement> result = new HashSet<ConcreteDiagramElement>();

    for (ConcreteBoundaryRectangle rec : getRectangles()) {
        result.addAll(rec.elementsInBoundingBox(topLeft, botRight));
    }//ww w  .  j  av a 2  s . com

    return result;
}

---

From source file:org.ontologyengineering.conceptdiagrams.web.shared.concretesyntax.ConcreteBoundaryRectangle.java

protected AbstractSet<ConcreteDiagramElement> getAllChildren() {
    AbstractSet<ConcreteDiagramElement> result = new HashSet<ConcreteDiagramElement>();
    result.addAll(getCurves());
    result.addAll(getSpiders());/*from www.  j  ava2s .  c om*/
    result.addAll(getArrows());
    result.addAll(getZones());
    return result;
}

---

From source file:org.ontologyengineering.conceptdiagrams.web.shared.concretesyntax.ConcreteBoundaryRectangle.java

public AbstractSet<ConcreteDiagramElement> elementsInBoundingBox(Point topLeft, Point botRight) {
    AbstractSet<ConcreteDiagramElement> result = new HashSet<ConcreteDiagramElement>();

    if (completelyEnclosed(topLeft, botRight)) {
        // we are completely inside the given bounds, so return everything, including this boundary rectangle
        result.add(this);
        result.addAll(getAllChildren());
    } else if (completelyEncloses(topLeft, botRight)) {
        // the bound is completely inside me
        result.addAll(elementsInBoundingBoxHelper(topLeft, botRight));
    } else {//from   w  ww.j  av  a  2s  . c  o  m
        if (ConcreteRectangularElement.rectanglesIntersect(topLeft(), bottomRight(), topLeft, botRight)) {
            // must intersect the rectangle so add that too
            result.add(this);
            result.addAll(elementsInBoundingBoxHelper(topLeft, botRight));
        }
    }
    return result;
}

---