Example usage for android.net Uri parse

Introduction

In this page you can find the example usage for android.net Uri parse.

Prototype

public static Uri parse(String uriString)

Source Link

Document

Creates a Uri which parses the given encoded URI string.

Usage

From source file:Main.java

public static Intent getSysAppDetailIntent(Context context) {
    return new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + context.getPackageName()));
}

From source file:Main.java

public static void ShowSoftInfoDialog(final Context context, String title, String msg) {
    AlertDialog alertDialog = new AlertDialog.Builder(context).setIcon(android.R.attr.alertDialogIcon)
            .setTitle(title).setMessage(msg).setPositiveButton("ok", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int whichButton) {

                    /* User clicked OK so do some stuff */
                }// w ww. ja  va2 s. c  om
            }).setNeutralButton("Email", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int whichButton) {
                    Uri uri = Uri.parse("mailto:atgczcl@163.com");
                    Intent emailIntent = new Intent(Intent.ACTION_SENDTO, uri);
                    context.startActivity(emailIntent);
                    /* User clicked Something so do some stuff */
                }
            }).create();
    alertDialog.show();

}

From source file:Main.java

public static String getInstagramId(String in) {

    Uri uri = Uri.parse(in);

    final String host = uri.getHost();

    if (TextUtils.isEmpty(host) == false && host.indexOf("instagram") >= 0) {
        return in;
    }//from w  w  w  .ja  va2  s  . c om

    return null;
}

From source file:Main.java

public static String encodeQuery(String url) {
    Uri uri = Uri.parse(url);

    try {/*w  w  w  .j  av  a2 s .c  om*/
        String query = uri.getQuery();
        String encodedQuery = query != null ? URLEncoder.encode(query, "UTF-8") : null;
        URI tmp = new URI(uri.getScheme(), uri.getAuthority(), uri.getPath(), null, uri.getFragment());
        return tmp + (encodedQuery != null && encodedQuery.length() > 0 ? "?" + encodedQuery : "");
    } catch (UnsupportedEncodingException ignore) {
    } catch (URISyntaxException ignore) {
    }

    return uri.toString();
}

From source file:Main.java

public static void CallPhone(Context context, String phone) {
    Intent intent = new Intent(Intent.ACTION_DIAL);
    Uri data = Uri.parse("tel:" + phone);
    intent.setData(data);//from   w  w  w  . j  a v a  2  s .c  om
    context.startActivity(intent);
}

From source file:Main.java

public static void downloadFile(Context context, String fileurl) {
    DownloadManager.Request request = new DownloadManager.Request(Uri.parse(fileurl));
    request.setDestinationInExternalPublicDir("/Download/", fileurl.substring(fileurl.lastIndexOf("/") + 1));
    DownloadManager downloadManager = (DownloadManager) context.getSystemService(Context.DOWNLOAD_SERVICE);
    downloadManager.enqueue(request);/*from ww  w .  j  av  a2 s  . c  o m*/
}

From source file:Main.java

public static void dial(Context ctx, String telephone) {
    try {//w w  w.  ja  v a 2  s .  c om
        if (telephone != null && !telephone.equals("")) {
            Uri uri = Uri.parse("tel:" + telephone);
            Intent intent = new Intent(Intent.ACTION_DIAL, uri);
            ctx.startActivity(intent);
        }
    } catch (Exception e) {
        e.printStackTrace();
    }

}

From source file:Main.java

public static boolean showMap(Context context, String address) {
    Uri addressUri = Uri.parse("geo:0,0?q=" + address);
    Intent searchAddress = new Intent(Intent.ACTION_VIEW, addressUri);

    boolean ret = true;
    try {//from  ww  w  .ja  v  a2 s . com
        context.startActivity(searchAddress);
    } catch (Exception e) {
        ret = false;
    }
    return ret;
}

From source file:Main.java

/**
 * When doing a web search, there are two situations.
 *
 * If user type in a url or something similar to a url, we need to
 * open the url directly for user. Otherwise, we just search the
 * content user type in with default search engine.
 *
 * @param str content user want to search or url user want to visit
 * @return intent/*from  w ww  .  j  ava 2  s . c om*/
 */
public static Intent getWebSearchIntent(String str) {
    Intent intent;
    // if search content contain ".", we think it's a url
    if (str.contains(".")) {
        if (!str.startsWith("http://") && !str.startsWith("https://"))
            str = "http://" + str;
        intent = new Intent(Intent.ACTION_VIEW, Uri.parse(str));
    } else {
        intent = new Intent(Intent.ACTION_WEB_SEARCH);
        intent.putExtra(SearchManager.QUERY, str);
    }
    return intent;
}

From source file:Main.java

/** Parses a string into a URI and returns null if the given string is null. */
public static Uri parseUriOrNull(String uriString) {
    if (uriString == null) {
        return null;
    }// ww  w.  j  a va  2s .  c o  m
    return Uri.parse(uriString);
}