Use the %u or %lu specifiers if your implementation does not recognize the %zd specifier in printf - C Language Basics

C examples for Language Basics:printf

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Description

Use the %u or %lu specifiers if your implementation does not recognize the %zd specifier in printf

Demo Code

#include <stdio.h>
#include <string.h>      /* provides strlen() prototype */

#define PRAISE "this is a test test test test."

int main(void)
{
    char name[40];
    //from   ww  w .j  av a2 s  .  c  o  m
    printf("What's your name? ");
    scanf("%s", name);
    printf("Hello, %s. %s\n", name, PRAISE);
    printf("Your name of %zd letters occupies %zd memory cells.\n", strlen(name), sizeof name);
    printf("It has %zd letters ", strlen(PRAISE));
    printf("and occupies %zd memory cells.\n", sizeof PRAISE);
    
    return 0;
}

Result


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