C - Write program to output double values in a given width

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Requirements

Define a function that will output an array of values of type double.

The double array is passed as an argument along with the number of elements in the array.

The prototype of the function will be the following: 

void show(double array[], int array_size, int field_width);

The values should be output five to a line, each with two places after the decimal point.

Demo

#define __STDC_WANT_LIB_EXT1__ 1
#include <stdio.h>
#include <string.h>
#include <ctype.h>

#define MAX_COUNT 100/*  w w  w.j  a va  2  s.  com*/

void show(double array[], size_t array_size, unsigned int field_width);

int main(void)
{
  double array[MAX_COUNT] = { 0.0 };
  size_t count = 0;
  for (double x = 1.5; x < 4.6; x += 0.3)
    array[count++] = x;

  unsigned int width = 12;
  show(array, count, width);

  printf_s("\n");
}

void show(double array[], size_t array_size, unsigned int field_width)
{
  char format[10] = { '\0' }; // Holds the format string
  unsigned int places = 2;
  sprintf_s(format, sizeof(format), "%%%u.%ulf", field_width, places);

  // Output the values five to a line
  for (size_t j = 0; j < array_size; ++j)
  {
    if (j % 5 == 0)
      printf_s("\n");

    printf_s(format, array[j]);
  }
}

Result

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