Returns true if a location is old. - Android Map

Android examples for Map:Location

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Description

Returns true if a location is old.

Demo Code

/*//from www . ja v a  2 s  . co  m
 * Copyright 2008 Google Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not
 * use this file except in compliance with the License. You may obtain a copy of
 * the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
 * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
 * License for the specific language governing permissions and limitations under
 * the License.
 */
import android.location.Location;

public class Main{
    private static final long MAX_LOCATION_AGE_MS = 60 * 1000;
    /**
     * Returns true if a location is old.
     * 
     * @param location the location
     */
    public static boolean isLocationOld(Location location) {
        return !LocationUtils.isValidLocation(location)
                || (System.currentTimeMillis() - location.getTime() > MAX_LOCATION_AGE_MS);
    }
    /**
     * Checks if a given location is a valid (i.e. physically possible) location
     * on Earth. Note: The special separator locations (which have latitude = 100)
     * will not qualify as valid. Neither will locations with lat=0 and lng=0 as
     * these are most likely "bad" measurements which often cause trouble.
     * 
     * @param location the location to test
     * @return true if the location is a valid location.
     */
    public static boolean isValidLocation(Location location) {
        return location != null && Math.abs(location.getLatitude()) <= 90
                && Math.abs(location.getLongitude()) <= 180;
    }
}

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