Construct a String from a code point array - Android java.lang

Android examples for java.lang:String Unicode

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Description

Construct a String from a code point array

Demo Code

/*//from   w  ww .j  a  v  a2s  .c  o  m
 * Copyright (C) 2012 The Android Open Source Project
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */


import android.text.TextUtils;
import java.util.Arrays;

public class Main{
    public static final int CAPITALIZE_NONE = 0; // No caps, or mixed case
    public static final int CAPITALIZE_FIRST = 1; // First only
    public static final int CAPITALIZE_ALL = 2; // All caps

    /**
     * Construct a String from a code point array
     *
     * @param codePoints a code point array that is null terminated when its logical length is
     * shorter than the array length.
     * @return a string constructed from the code point array.
     star/
    public static String getStringFromNullTerminatedCodePointArray(final int[] codePoints) {
        int stringLength = codePoints.length;
        for (int i = 0; i < codePoints.length; i++) {
            if (codePoints[i] == 0) {
                stringLength = i;
                break;
            }
        }
        return new String(codePoints, 0 /star offset star/, stringLength);
    }*/

    // This method assumes the text is not null. For the empty string, it returns CAPITALIZE_NONE.
    public static int getCapitalizationType(final String text) {
        // If the first char is not uppercase, then the word is either all lower case or
        // camel case, and in either case we return CAPITALIZE_NONE.
        final int len = text.length();
        int index = 0;
        for (; index < len; index = text.offsetByCodePoints(index, 1)) {
            if (Character.isLetter(text.codePointAt(index))) {
                break;
            }
        }
        if (index == len)
            return CAPITALIZE_NONE;
        if (!Character.isUpperCase(text.codePointAt(index))) {
            return CAPITALIZE_NONE;
        }
        int capsCount = 1;
        int letterCount = 1;
        for (index = text.offsetByCodePoints(index, 1); index < len; index = text
                .offsetByCodePoints(index, 1)) {
            if (1 != capsCount && letterCount != capsCount)
                break;
            final int codePoint = text.codePointAt(index);
            if (Character.isUpperCase(codePoint)) {
                ++capsCount;
                ++letterCount;
            } else if (Character.isLetter(codePoint)) {
                // We need to discount non-letters since they may not be upper-case, but may
                // still be part of a word (e.g. single quote or dash, as in "IT'S" or "FULL-TIME")
                ++letterCount;
            }
        }
        // We know the first char is upper case. So we want to test if either every letter other
        // than the first is lower case, or if they are all upper case. If the string is exactly
        // one char long, then we will arrive here with letterCount 1, and this is correct, too.
        if (1 == capsCount)
            return CAPITALIZE_FIRST;
        return (letterCount == capsCount ? CAPITALIZE_ALL : CAPITALIZE_NONE);
    }

}

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