Android XPath Evaluate asNodeList(String nodeName, Node node)

Description

as Node List

License

Open Source License

Declaration

public static NodeList asNodeList(String nodeName, Node node)
            throws XPathExpressionException 

Method Source Code

//package com.java2s;
/*//from w  ww  . j a  v a 2s.c om
 * Copyright 2010-2013 Amazon.com, Inc. or its affiliates. All Rights Reserved.
 *
 * Licensed under the Apache License, Version 2.0 (the "License").
 * You may not use this file except in compliance with the License.
 * A copy of the License is located at
 *
 *  http://aws.amazon.com/apache2.0
 *
 * or in the "license" file accompanying this file. This file is distributed
 * on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either
 * express or implied. See the License for the specific language governing
 * permissions and limitations under the License.
 */

import javax.xml.xpath.XPathExpressionException;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static NodeList asNodeList(String nodeName, Node node)
            throws XPathExpressionException {
        if (node == null)
            return null;
        return findXPathNodeList(node, nodeName);
    }

    private static NodeList findXPathNodeList(Node node, String xPath) {
        int currentSearchIndex = 0;
        while (currentSearchIndex < xPath.length()) {

            int endingIndex = xPath.indexOf("/", currentSearchIndex);

            String noderNameFromXPath = null;
            if (endingIndex == -1) {
                noderNameFromXPath = xPath.substring(currentSearchIndex);
            } else {
                noderNameFromXPath = xPath.substring(currentSearchIndex,
                        endingIndex);
            }

            node = findChildNodeWithName(node, noderNameFromXPath);

            if (endingIndex == -1) {
                break;
            }

            currentSearchIndex = endingIndex + 1;
        }

        return node.getChildNodes();
    }

    private static Node findChildNodeWithName(Node node, String childName) {
        if (node == null) {
            return null;
        } else {
            if (node.getNodeName().equals(childName)) {
                return node;
            } else {
                NodeList nodeList = node.getChildNodes();
                for (int i = 0; i < nodeList.getLength(); i++) {
                    if (nodeList.item(i).getNodeName().equals(childName)) {
                        return nodeList.item(i);
                    }
                }

                return null;
            }
        }
    }
}

Related

1. asString(String expression, Node node)
2. asNode(String nodeName, Node node)
3. asLong(String expression, Node node)
4. asInteger(String expression, Node node)
5. asFloat(String expression, Node node)
6. asDouble(String expression, Node node)