List of utility methods to do String to Number Convert
boolean | isNumeric(String str) is Numeric final String number = "0123456789"; for (int i = 0; i < str.length(); i++) { if (number.indexOf(str.charAt(i)) == -1) { return false; return true; |
boolean | isNumeric(String str) is Numeric Pattern pattern = Pattern.compile("^[-\\+]?[\\d]*$"); return pattern.matcher(str).matches(); |
boolean | isNumeric(String str) is Numeric int index = str.indexOf("."); if (index == -1) { return isIntegral(str); if ((index == 0) || (index == str.length() - 1)) { return false; String num1 = str.substring(0, index); ... |
boolean | isNumeric(String str) is Numeric Pattern pattern = Pattern.compile("[0-9]*"); Matcher isNum = pattern.matcher(str); if (!isNum.matches()) { return false; return true; |
boolean | isNumeric(String string) Tests if a string is numeric, i.e. if (string == null || string.length() == 0) return false; int l = string.length(); for (int i = 0; i < l; i++) { if (!Character.isDigit(string.codePointAt(i))) return false; return true; ... |
boolean | isLetterNumeric(String s) Return true if the string is alphanum. int i = 0, len = s.length(); while (i < len && (Character.isLowerCase(s.charAt(i)) || Character.isUpperCase(s.charAt(i)) || Character .isDigit(s.charAt(i)))) { i++; return (i >= len); ... |
boolean | isNumericOnly(String pString) is Numeric Only return Pattern.matches("[0-9[-\\s]]+", pString); |
boolean | isNumeric(String str) is Numeric if (str == null || str.length() == 0) { return false; Pattern pattern = Pattern.compile("[0-9]*"); return pattern.matcher(str).matches(); |
boolean | containsNonNumericCharacters(String rawInput) contains Non Numeric Characters Pattern p = Pattern.compile("(\\D+)"); Matcher m = p.matcher(rawInput); return m.find(); |
Boolean | isNumber(String str) is Number Boolean isNumber = false; String expr = "^[0-9]+$"; if (str.matches(expr)) { isNumber = true; return isNumber; |