Android String to Long Convert parseLong(String s, long iDefault)

Here you can find the source of parseLong(String s, long iDefault)

Description

Parses the long value of the specified string.

License

Apache License

Parameter

Parameter Description
s The string value to parse.
iDefault A default long value.

Return

A long value parsed from the specified string.

Declaration

public static long parseLong(String s, long iDefault) 

Method Source Code

//package com.java2s;
/*/*www .  j ava2 s.  c  o  m*/
 * Copyright 2012 AT&T
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    /**
     * Parses the long value of the specified string.
     * 
     * @param s
     *            The string value to parse.
     * @param iDefault
     *            A default long value.
     * @return A long value parsed from the specified string.
     */
    public static long parseLong(String s, long iDefault) {
        if (s == null || s.equals(""))
            return iDefault;
        try {
            s = s.trim().replaceAll(",", "");
            final int l = s.indexOf('.');
            if (l > 0)
                s = s.substring(0, l);
            return Long.parseLong(s);
        } catch (RuntimeException e) {
            return iDefault;
        }
    }
}

Related

  1. stringToLong(String input)
  2. longsToString(long... longs)
  3. parseCSLongs(String s)
  4. parseLong(String s)
  5. parseLongWithDefault(String s, long defValue)
  6. safeParseLong(String number, long fallback)