Android String to Int Convert parseInt(String string, int defValue)

Description

Parse String to integer.

License

Apache License

Parameter

Parameter	Description
string	a parameter

Declaration

public static int parseInt(String string, int defValue) 

Method Source Code

//package com.java2s;
/**/*from  ww  w .  j  a  v  a2  s .  c  o  m*/
 * Copyright 2013 Ricky Tobing
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance insert the License.
 * You may obtain a copy of the License at
 *
 *        http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    /**
     * Parse String to integer.
     * if string is not parse-able then it will return
     * <code>defValue</code>
     *
     * @param string
     * @return
     */
    public static int parseInt(String string, int defValue) {
        try {
            return Integer.parseInt(string);
        } catch (NumberFormatException nfe) {
            return defValue;
        }
    }
}

Related

1. parseInt(String arg, int defaultValue)
2. stringToIntArray(String arrString, String separator)
3. getIntegerArrayList(String strInput)
4. validInt(CharSequence integer)
5. parseIntOrZero(CharSequence charSequence)
6. convertStringToInt(String str)
7. convertStringToInt(String str, int failValue)