Android String Contain containCount(String str, String searchStr)

Description

contain Count

License

Apache License

Declaration

public static int containCount(String str, String searchStr) 

Method Source Code

//package com.java2s;
/**/*w  w w.  j av a2s  .  c  om*/
 * Copyright 2013 ??????
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    public static final String EMPTY = "";
    public static final int INDEX_NOT_FOUND = -1;

    public static int containCount(String str, String searchStr) {
        int i = 0;
        int idx = 0;

        if (str == null || searchStr == null) {
            return 0;
        }
        while (true) {
            if ((idx = str.indexOf(searchStr)) > INDEX_NOT_FOUND) {
                str = substring(str, (idx + searchStr.length()),
                        str.length());
                i++;
            } else {
                break;
            }
        }

        return i;
    }

    public static String substring(String str, int beginIndex) {
        if (str == null) {
            return null;
        }

        if (beginIndex < 0) {
            return EMPTY;
        }

        if (beginIndex > str.length()) {
            return EMPTY;
        }

        return str.substring(beginIndex);
    }

    public static String substring(String str, int beginIndex, int endIndex) {
        if (str == null) {
            return null;
        }

        if (beginIndex < 0 || endIndex < 0) {
            return EMPTY;
        }

        if (endIndex > str.length()) {
            endIndex = str.length();
        }

        if (beginIndex > endIndex || beginIndex > str.length()) {
            return EMPTY;
        }

        return str.substring(beginIndex, endIndex);
    }
}

Related

1. contains(String str1, String str2)
2. checkContainSpace(final String x)
3. containsCharRef(String s)
4. contains(final CharSequence seq, final CharSequence searchSeq)
5. contains(String str, String searchStr)
6. contains(String[] str, String searchStr)
7. contains(String str, List keywords)
8. cutWords(String src, String contains)