Android Phone Number Check isPhoneNumber(String phoneNum)

Description

is Phone Number

License

Open Source License

Declaration

public static boolean isPhoneNumber(String phoneNum) 

Method Source Code

//package com.java2s;
/*//from  ww  w  .  jav a  2s.c o  m
 *  Copyright (C) 2014 The AppCan Open Source Project.
 *
 *  This program is free software: you can redistribute it and/or modify
 *  it under the terms of the GNU Lesser General Public License as published by
 *  the Free Software Foundation, either version 3 of the License, or
 *  (at your option) any later version.

 *  This program is distributed in the hope that it will be useful,
 *  but WITHOUT ANY WARRANTY; without even the implied warranty of
 *  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 *  GNU Lesser General Public License for more details.

 *  You should have received a copy of the GNU Lesser General Public License
 *  along with this program.  If not, see <http://www.gnu.org/licenses/>.
 *
 */

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {

    public static boolean isPhoneNumber(String phoneNum) {
        String expression = "^((13[0-9])|(15[^4,\\D])|(18[0,5-9]))\\d{8}$";
        CharSequence inputStr = phoneNum;
        Pattern pattern = Pattern.compile(expression);
        Matcher matcher = pattern.matcher(inputStr);
        if (matcher.matches()) {
            return true;
        }
        return false;

    }
}

Related

1. isTelNumAvailable(String telNum)
2. isMobile(String mobiles)
3. isMobileNO(String phoneNum)
4. isLegalPhoneNumber(String phoneNumber)
5. checkPhone(String phone)