Android Long Bit Set nextHighestPowerOfTwo(long v)

Here you can find the source of nextHighestPowerOfTwo(long v)

Description

returns the next highest power of two, or the current value if it's already a power of two or zero

License

Apache License

Declaration

public static long nextHighestPowerOfTwo(long v) 

Method Source Code

//package com.java2s;
/**/*  w  ww . ja va  2 s.c om*/
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    /** returns the next highest power of two, or the current value if it's already a power of two or zero*/
    public static int nextHighestPowerOfTwo(int v) {
        v--;
        v |= v >> 1;
        v |= v >> 2;
        v |= v >> 4;
        v |= v >> 8;
        v |= v >> 16;
        v++;
        return v;
    }

    /** returns the next highest power of two, or the current value if it's already a power of two or zero*/
    public static long nextHighestPowerOfTwo(long v) {
        v--;
        v |= v >> 1;
        v |= v >> 2;
        v |= v >> 4;
        v |= v >> 8;
        v |= v >> 16;
        v |= v >> 32;
        v++;
        return v;
    }
}

Related

  1. pop_andnot(long A[], long B[], int wordOffset, int numWords)
  2. pop_array(long A[], int wordOffset, int numWords)
  3. pop_intersect(long A[], long B[], int wordOffset, int numWords)
  4. pop_union(long A[], long B[], int wordOffset, int numWords)