Android Folder File List getFileNames(String dirPath, FilenameFilter fileNameFilter)

Here you can find the source of getFileNames(String dirPath, FilenameFilter fileNameFilter)

Description

get File Names

License

Open Source License

Declaration

public static String[] getFileNames(String dirPath,
            FilenameFilter fileNameFilter) throws Exception 

Method Source Code

//package com.java2s;
/*/*from   w  w  w . j  a  v a  2s .  c om*/
 * IzPack - Copyright 2001-2008 Julien Ponge, All Rights Reserved.
 *
 * http://izpack.org/
 * http://izpack.codehaus.org/
 *
 * Copyright 2005 Marc Eppelmann
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.io.*;

public class Main {
    public static String[] getFileNames(String dirPath) throws Exception {
        return getFileNames(dirPath, null);
    }

    public static String[] getFileNames(String dirPath,
            FilenameFilter fileNameFilter) throws Exception {
        String fileNames[] = null;
        File dir = new File(dirPath);
        if (dir.isDirectory()) {
            if (fileNameFilter != null) {
                fileNames = dir.list(fileNameFilter);
            } else {
                fileNames = dir.list();
            }
        }
        return fileNames;
    }
}

Related

  1. ListFiles(File dir, FilenameFilter filter)
  2. getAllFilesAndFolders(File root, boolean containEmpty)
  3. getFileNames(String dirPath)
  4. getFiles(File dir, List outList)
  5. listFiles(String fileName)
  6. pathContains(String root, String child)
  7. listFile(File file)