PHP strrpos() Function

Definition

The strrpos() function finds the position of the last occurrence of a string inside another string (case-sensitive).

Syntax

PHP strrpos() Function has the following syntax.

Parameter

Return

PHP strrpos() Function returns the position of the last occurrence of a string inside another string, or FALSE if the string is not found.

Related functions

• strpos() - Finds the position of the first occurrence of a string inside another string (case-sensitive)
• stripos() - Finds the position of the first occurrence of a string inside another string (case-insensitive)
• strripos() - Finds the position of the last occurrence of a string inside another string (case-insensitive)

Example 1

Find the position of the last occurrence of "php" inside the string:

<?php// w  ww. j a v  a  2  s  .  c  om
echo strrpos("php, from java2s.com!","php");

$myString = "Hello, world!"; 
echo strpos( $myString, "o" ) . "\n";  // Displays '4' 
echo strrpos( $myString, "o" ) . "\n"; // Displays '8'   
?>

The code above generates the following result.

Example

When the searched text occurs at the start of the string. In this case, strpos() returns 0 (the index of the first character of the found text), but it's easy to mistake this for a return value of false if you're not careful.

For example, the following code will incorrectly display "Not found" :

<?PHP//from  w  w w  .  j  av a 2s  . c  o  m
   $myString = "Hello, world!"; 
   if ( !strrpos( $myString, "Hel" ) ) {
      echo "Not found";   
   }   
?>

So you need to test explicitly for a false return value, if that's what you're checking for.

The following code works correctly:

<?PHP/* w w w. j a va 2 s. c  om*/
   $myString = "Hello, world!"; 
   if ( strrpos( $myString, "Hel" ) === false ){
       echo "Not found";   
   }
?>