Java BlockingDeque.putLast(E e)
Syntax
BlockingDeque.putLast(E e) has the following syntax.
void putLast(E e) throws InterruptedException
Example
In the following code shows how to use BlockingDeque.putLast(E e) method.
//w ww .ja v a 2s . c om
import java.util.concurrent.BlockingDeque;
import java.util.concurrent.LinkedBlockingDeque;
import java.util.concurrent.TimeUnit;
class Producer implements Runnable {
private String name;
private BlockingDeque<Integer> deque;
public Producer(String name, BlockingDeque<Integer> deque) {
this.name = name;
this.deque = deque;
}
public synchronized void run() {
for (int i = 0; i < 10; i++) {
try {
deque.putLast(i);
System.out.println(name + " puts " + i);
Thread.sleep(300);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
class Consumer implements Runnable {
private String name;
private BlockingDeque<Integer> deque;
public Consumer(String name, BlockingDeque<Integer> deque) {
this.name = name;
this.deque = deque;
}
public synchronized void run() {
for (int i = 0; i < 10; i++) {
try {
int j = deque.takeLast();
System.out.println(name + " takes " + j);
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public class Main {
public static void main(String[] args) {
BlockingDeque<Integer> deque = new LinkedBlockingDeque<Integer>(5);
Runnable producer = new Producer("Producer", deque);
Runnable consumer = new Consumer("Consumer", deque);
new Thread(producer).start();
try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
new Thread(consumer).start();
}
}
The code above generates the following result.