Java Long.parseLong(String s)
Syntax
Long.parseLong(String s) has the following syntax.
public static long parseLong(String s) throws NumberFormatException
Example
In the following code shows how to use Long.parseLong(String s) method.
public class Main {
public static void main(String[] args) {
System.out.println(Long.parseLong("12345"));
/*from w ww . j a va2 s .c o m*/
}
}
The output:
