OCA Java SE 8 Mock Exam - OCA Mock Question 23








Question

What is the output of the following code? 

public class Main { 
    int tryAgain() { 
        int a = 10; 
        try { 
            ++a; 
        } 
        finally { 
            a++; 
        } 
        return a; 
    } 
    public static void main(String args[]) { 
        System.out.println(new Main().tryAgain()); 
    } 
}
  1. 10
  2. 11
  3. 12
  4. Compilation error
  5. Runtime exception




Answer



C

Note

The try block executes, incrementing the value of variable a to 11.

This step is followed by execution of the finally block, which also increments the value of variable a by 1, to 12.

The method tryAgain returns the value 12, which is printed by the method main. 

public class Main { 
    int tryAgain() { 
        int a = 10; 
        try { /* ww w .  jav  a2s  .c o  m*/
            ++a; 
        } 
        finally { 
            a++; 
        } 
        return a; 
    } 
    public static void main(String args[]) { 
        System.out.println(new Main().tryAgain()); 
    } 
}

There are no compilation issues with the code. A try block can be followed by a finally block, without any catch blocks.

Even though the try block doesn't throw any exceptions, it compiles successfully.

The code above generates the following result.