C# Math Round(Double, MidpointRounding)
Description
Math Round(Double, MidpointRounding)
rounds a double-precision
floating-point value to the nearest integer. A parameter specifies how
to round the value if it is midway between two numbers.
Syntax
Math.Round(Double, MidpointRounding)
has the following syntax.
public static double Round(
double value,
MidpointRounding mode
)
Parameters
Math.Round(Double, MidpointRounding)
has the following parameters.
value
- A double-precision floating-point number to be rounded.mode
- Specification for how to round value if it is midway between two other numbers.
Returns
Math.Round(Double, MidpointRounding)
method returns The integer nearest value. If value is halfway between two integers, one
of which is even and the other odd, then mode determines which of the two is
returned.
Example
In the following example, because the floating-point value .1 has no finite binary representation, the first call to the Round(Double) method with a value of 11.5 returns 11 instead of 12.
using System;/* ww w .ja v a 2 s .com*/
public class Example
{
public static void Main()
{
double value = 11.1;
for (int ctr = 0; ctr <= 5; ctr++){
value = RoundValueAndAdd(value);
}
value = 11.5;
RoundValueAndAdd(value);
}
private static double RoundValueAndAdd(double value)
{
Console.WriteLine("{0} --> {1}", value, Math.Round(value,
MidpointRounding.AwayFromZero));
return value + .1;
}
}
The code above generates the following result.