C# Int16 TryParse(String, Int16)

Description

Int16 TryParse(String, Int16) converts the string representation of a number to its 16-bit signed integer equivalent. A return value indicates whether the conversion succeeded or failed.

Syntax

Int16.TryParse(String, Int16) has the following syntax.

public static bool TryParse(
  string s,
  out short result
)

Parameters

Int16.TryParse(String, Int16) has the following parameters.

• s - A string containing a number to convert.
• result - When this method returns, contains the 16-bit signed integer value equivalent to the number contained in s, if the conversion succeeded, or zero if the conversion failed. The conversion fails if the s parameter is null or String.Empty, is not of the correct format, or represents a number less than MinValue or greater than MaxValue. This parameter is passed uninitialized.

Returns

Int16.TryParse(String, Int16) method returns true if s was converted successfully; otherwise, false.

Example

The following example calls the Int16.TryParse(String, Int16)method with a number of different string values.

using System;/*w  w w  .  j  av a  2s  .c  o m*/

public class StringParsing
{
   public static void Main()
   {
      TryToParse(null);
      TryToParse("12345");
      TryToParse("1234.0");
      TryToParse("16,667");
      TryToParse("   -123   ");
      TryToParse("+1234");
      TryToParse("(123);");
      TryToParse("01FA");
   }

   private static void TryToParse(string value)
   {
      short number;
      bool result = Int16.TryParse(value, out number);
      if (result)
      {
         Console.WriteLine("Converted '{0}' to {1}.", value, number);         
      }
      else
      {
         if (value == null) value = ""; 
         Console.WriteLine("Attempted conversion of '{0}' failed.", value);
      }
   }
}

The code above generates the following result.