C# FileInfo Open(FileMode, FileAccess)
Description
FileInfo Open(FileMode, FileAccess) Opens a file in
the specified mode with read, write, or read/write access.
Syntax
FileInfo.Open(FileMode, FileAccess) has the following syntax.
public FileStream Open(
FileMode mode,
FileAccess access
)
Parameters
FileInfo.Open(FileMode, FileAccess) has the following parameters.
mode- A FileMode constant specifying the mode (for example, Open or Append) in which to open the file.access- A FileAccess constant specifying whether to open the file with Read, Write, or ReadWrite file access.
Returns
FileInfo.Open(FileMode, FileAccess) method returns A FileStream object opened in the specified mode and access, and unshared.
Example
The following example opens a file as read-only and reads from the file.
//from www .ja v a 2 s. co m
using System;
using System.IO;
using System.Text;
class Test
{
public static void Main()
{
string path = @"c:\MyTest.txt";
FileInfo fi = new FileInfo(path);
using (FileStream fs = fi.Open(FileMode.Open, FileAccess.Read))
{
byte[] b = new byte[1024];
UTF8Encoding temp = new UTF8Encoding(true);
while (fs.Read(b,0,b.Length) > 0)
{
Console.WriteLine(temp.GetString(b));
}
try
{
//Try to write to the file.
fs.Write(b,0,b.Length);
}
catch (Exception e)
{
Console.WriteLine("Writing was disallowed, as expected: {0}",
e.ToString());
}
}
}
}