C# DirectoryInfo GetFiles()
Description
DirectoryInfo GetFiles() Returns a file list from the
current directory.
Syntax
DirectoryInfo.GetFiles() has the following syntax.
public FileInfo[] GetFiles()
Returns
DirectoryInfo.GetFiles() method returns
Example
Returns a file list from the current directory.
using System;/*from w ww. j a v a2s . c o m*/
using System.IO;
class Program
{
static void Main(string[] args)
{
DirectoryInfo di = new DirectoryInfo(@"C:\Users\");
foreach (var fi in di.GetFiles())
{
Console.WriteLine(fi.Name);
}
Console.WriteLine("Search pattern *2* returns:");
foreach (var fi in di.GetFiles("*2*"))
{
Console.WriteLine(fi.Name);
}
Console.WriteLine("Search pattern test?.txt returns:");
foreach (var fi in di.GetFiles("test?.txt"))
{
Console.WriteLine(fi.Name);
}
Console.WriteLine("Search pattern AllDirectories returns:");
foreach (var fi in di.GetFiles("*", SearchOption.AllDirectories))
{
Console.WriteLine(fi.Name);
}
}
}
The code above generates the following result.
