LEFT(CompanyName, 1) and like : LEFT « String Functions « SQL Server / T-SQL Tutorial






24> CREATE TABLE Customers (
25>     CustomerID nchar (5) NOT NULL ,
26>     CompanyName nvarchar (40) NOT NULL ,
27>     ContactName nvarchar (30) NULL ,
28>     ContactTitle nvarchar (30) NULL ,
29>     Address nvarchar (60) NULL ,
30>     City nvarchar (15) NULL ,
31>     Region nvarchar (15) NULL ,
32>     PostalCode nvarchar (10) NULL ,
33>     Country nvarchar (15) NULL ,
34>     Phone nvarchar (24) NULL ,
35>     Fax nvarchar (24) NULL
36> )
37> GO
1>
2> INSERT Customers VALUES('1','A','Maria',    'Sales',  'Str. 57', 'Berlin'    ,NULL,'12209', 'Germany','111-1111111','111-1111111')
3> INSERT Customers VALUES('2','M','Joe',      'Owner',  'Ave. 231','Vancouver' ,NULL,'05023', 'Mexico', '(222) 222-3332',NULL)
4> INSERT Customers VALUES('3','H','Thomas',   'Sales',  'Sq.  111','London'    ,NULL,'1D00P', 'UK',     '(444) 444-4444','(444) 444-4444')
5> INSERT Customers VALUES('4','B','Berg',     'Order',  'Blv    8','Toronto'   ,NULL,'00222', 'Sweden', '4444-55 55 65','5555-55 55 55')
6> INSERT Customers VALUES('5','S','Moos',     'Sales',  'Fort  57','New York'  ,NULL,'68306', 'Germany','6666-66666','6666-77777')
7> INSERT Customers VALUES('6','F','Cite',     'Manager','24      ','Dalles'    ,NULL,'67000', 'France', '88.60.15.31','88.60.15.32')
8> INSERT Customers VALUES('7','C','Sommer',   'Owner',  'Araq, 67','Paris'     ,NULL,'28023', 'Spain',  '(91) 555 22 82','(91) 555 91 99')
9> INSERT Customers VALUES('8','P','Leb',      'Owner',  '12      ','Beijing'   ,NULL,'13008', 'France', '91.24.45.40','91.24.45.41')
10> INSERT Customers VALUES('9','D','Elizabeth','Manager','23 Blvd.','Tsawassen','BC', 'T2F8M4','Canada', '(604) 555-4729','(604) 555-3745')
11> go
1>
2>
3> SELECT CustomerID, CompanyName, Country
4> FROM dbo.Customers
5> WHERE LEFT(CompanyName, 1) = N'A';
6> GO
CustomerID CompanyName                              Country
---------- ---------------------------------------- ---------------
1          A                                        Germany
1> SELECT CustomerID, CompanyName, Country
2> FROM dbo.Customers
3> WHERE CompanyName LIKE N'A%';
4> GO
CustomerID CompanyName                              Country
---------- ---------------------------------------- ---------------
1          A                                        Germany
1>
2> drop table Customers;
3> GO








12.6.LEFT
12.6.1.LEFT function returns a number of characters from the left-hand side of a string.
12.6.2.select LEFT('SQL Server', 3)
12.6.3.Taking the Leftmost or Rightmost Part of a String
12.6.4.A SELECT statement that uses the LEFT function
12.6.5.Use LEFT and RIGHT to get sub value from a column
12.6.6.LEFT(CompanyName, 1) and like
12.6.7.How to use the string functions to parse a string