Define variable used by lambda function outside : lambda « Function « Python Tutorial






  1. Python Tutorial
  2. Function
  3. lambda
def weird():
    tmp = (lambda: spam * 2)        
    spam = 42                       
    return tmp

act = weird()
print act()








10.11.lambda
10.11.1.If a function body is a single return expression statement, you may choose to replace the function with the special lambda expression form
10.11.2.The lambda operator creates anonymous functions: lambda args : expression
10.11.3.Using lambda Functions: define one-line mini-functions on the fly
10.11.4.A lambda function squares the members of a sequence:
10.11.5.Anonymous Functions and lambda: lambda [arg1[, arg2, ... argN]]: expression
10.11.6.Define variable used by lambda function outside
10.11.7.Lookup variable used in lambda
10.11.8.Applying Functions to Arguments