Use ClassPathXmlApplicationContext : ClassPathXmlApplicationContext « Spring « Java Tutorial






File: context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
            http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd">

    <bean id="test" class="TestBean">
        <property name="name" value="${name}"/>
    </bean>

    <context:property-placeholder location="classpath:test.properties" />
    <context:component-scan base-package="*"/>

</beans>

File: Main.java

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class Main {
  public static void main(String[] z) {
    ApplicationContext context = new ClassPathXmlApplicationContext("context.xml", Main.class);
    TestBean testBean = (TestBean)context.getBean("test");
    System.out.println(testBean);
  }

}
class TestBean {
  private String name;

  public String getName() {
      return name;
  }

  public void setName(String name) {
      this.name = name;
  }

  @Override
  public String toString() {
      final StringBuilder sb = new StringBuilder();
      sb.append("TestBean");
      sb.append("{name='").append(name).append('\'');
      sb.append('}');
      return sb.toString();
  }
}

File: test.properties

name=AAA
  Download:  Spring-component-scan.zip( 4,649 k)








28.12.ClassPathXmlApplicationContext
28.12.1.Use ClassPathXmlApplicationContext
28.12.2.Class Path Xml ApplicationContext